Asample of air with a volume of 2.20m3 at a pressure of 105 kpa and a temperature of 30c is cooled to 10c and the pressure is reduced to 75.0 kpa. what is the new volume? 6.9 1.34 2.56 43.0 2.88

The answer is 2.88 m3

Explanation: Since temperature, pressure and volume are given in the question, the general gas equation will be useful in calculating the new volume.

General gas equation,

(P1V1)/T1 = (P2V2) /T2 (1)

Where,

P1 = Initial pressure

P2 = Final pressure

V1 = Initial volume

V2 = Final volume

T1 = Initial temperature in kelvin

T2 = Final temperature in Kelvin

Hence, from the question :

P1 = 105 KPa = 105,000 Pa

P2 = 75 KPa = 75,000 Pa

V1 = 2.20 m3

V2 =?

T1 = 30 °C = (273+30) K = 303 K

T2 =10 °C = (273+10) K = 283 K

Therefore, substitute these value into the general gas equation as given in eq (1) above.

V2 = (P1V1T2) /P2V1

V2 = (105000×2.2×283)/ (75000×303)

V2 = 2.88 m3

a is the answer

explanation:

which statement about trans-fatty acids is false?

a. the conversion of cis-fatty acids to trans-fatty acids is inhibited by the presence of antioxidants.

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