If the solubility of a gas in water is 1.22 g/l at 2.75 atm, what is its solubility (in g/l) at 1.0 atm?

0.44 g/L.

Explanation:

This problem is an application on Henry's law.Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.Solubility of the gas ∝ partial pressureIf we have different solubility at different pressures, we can express Henry's law as: S₁/P₁ = S₂/P₂,S₁ = 1.22 g/L and P₁ = 2.75 atmS₂ = ??? g/L and P₂ = 1.0 atmSo, The solubility of the gas at 1.0 atm (S₂) = S₁.P₂/P₁ = (1.22 g/L x 1.0 atm) / (2.75 atm) = 0.44 g/L.

It's a