The radius of a copper atom is 128 pm. how many copper atoms would have to be laid side by side to span a distance of 4.65 mm?

The distance covered by each atom of copper will be twice the radius of each atom, which is its diameter

it will be like as shown in diagram....

Let the number of atoms required is "n"

thus total atoms required will be

Let us convert pm to mm for unit cancellation.

Thus

hence

by cartels in other countries, shipped by air, mail, or land. i cant really see your answer choices : /

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g