In the formation of ammonia, if pressure is decreased, what will happen to the equilibrium of the system? a. it will shift to the right because there are more moles of gas on the product side. b. it will shift in neither direction because pressure does not affect chemical equilibrium. c. it will shift to the left because there are more moles of gas on the reactant side.

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.