Concentrated aqueous nitric acid is 70.4 wt% hno3 and has a concentration of 15.9 m. calculate the volume of concentrated nitric acid that should be diluted to 1.80 l to form a 5.00 m hno3 solution.

The volume should be taken from the stock is 0.5335 L = 533.5 ml.

Explanation:

Firstly, we must calculate the molarity of the HNO₃, M = (10pd / Molar mass), where p is the weight percent (70.4 %), d is the specific garvity of HNO₃ (d = 1.51 g/cm³) and molar mass = 63.01 g/mole.Now, Molarity of the stock M = 10pd/ Molar mass = (10 x 70.4 x 1.51) / (63.01) = 16.87 M.To calculate the volume needed to prepare 1.80 L with 5.0 M concentration, we use the rule that the number of millimoles before dilution is equal to the number of millimoles after the dilution.

(MV) before dilution = (MV) after dilution

The volume should be taken from the stock = (MV) after dilution / M before the dilution = (5.0 M x 1.80 L) / 16.87 M = 0.5335 L = 533.5 ml.

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