Place the following compounds in order of increasing strength of intermolecular forces. ch4 ch3ch2ch3 ch3ch3

Explanation:

More is the mass of an alkane molecule more will be its boiling point. This means that forces of attraction will be more when mass is more as more heat is required to break the bonds within atoms. Hence, boiling point is more.

Therefore, in the given molecules mass of is 16.04 g/mol, mass of is 44 g/mol, and mass of is 30 g/mol.

Thus, we can see that has the highest mass and has least mass.

Hence, increasing strength of intermolecular forces of given compounds is as follows.

is has three carbons, so the answer is propylamine.

meth-

eth-

prop-

but-

pent-

hex-

hept-

oct-

non-

explanation:

the answer to your question is c