Calculate the molality of 2.0 m mgcl2 solution. the density of the solution is 1.127 g/ml. (the molar mass of mgcl2 = 95.211 g/mol and the molar mass of h2o is 18.02 g/mol.)

The answer is 2.135 mol/Kg

Given that molarity is 2M, that is, 2 moles in 1 liter of solution.

Density of solution is 1.127 g/ml

Volume of solution is 1L or 1000 ml

mass of solution (m) = density × volume

m₁ = density × volume = 1.127 × 1000 = 1127 g

mass of solute, m₂ = number of moles × molar mass

m₂ = 2 × 95.211

m₂ = 190.422 g

mass of solvent = m₁ - m₂

= 1127 - 190.422

= 936.578 g

= 0.9366 Kg

molality = number of moles of solute / mass of solvent (in kg)

= 2 / 0.9366

= 2.135 mol/Kg

2b2t

explanation:

2b2t

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be