One method for determine the purity of a sample of titanium ( iv) oxide, an important industrial chemical, is to combine the sample with bromine trifluoride to produce titanium ( iv) fluoride, liquid bromine , and oxygen has. suppose 2.367g of an impure sample( impure meaning that the sample has titanium (iv) oxide as well as other “ stuff” in it ) evolves 0.143 g of oxygen gas. what is the mass percent of titanium ( iv) oxide in the impure sample?

The reaction between titanium ( IV) oxide and bromine trifluoride to give  liquid bromine , and oxygen is:

Thus from each three moles of  titanium ( IV) oxide we will get three moles of oxygen molecule

The mass of oxygen obtained = 0.143g

The moles of oxygen obtained

      =

So moles of  titanium ( IV) oxide required will be 0.00447mol

the molar mass of  titanium ( IV) oxide is 79.87g/mol

mass of titanium ( IV) oxide used will be =

This mass of  titanium ( IV) oxide is present in 2.367g of impure sample

the mass percent will be

The percentage of titanium ( IV) oxide in impure sample is 15.08% (w/w)

2b2t

explanation:

2b2t

50.23 i believe is correct but don't quote me on that.