What is the percentage composition of nahco3

The % of Na is 27.365 %.

The % of H is 1.20 %.

The % of C is 14.30 %.

The % of O is 57.13 %.

Explanation:

The composition of NaHCO₃ shows that it contains 1.0 atom of Na, 1.0 atom of H and 3.0 atoms of O.The molar mass of NaHCO₃ = ∑(no. of atoms x Atomic mass of the element).Atomic mass of Na = 22.99 g/mole, atomic mass of H = 1.01 g/mole, atomic mass of C = 12.01 g/mole, and atomic mass of O = 16.00 g/mole.Then, the molar mass of NaHCO₃ = (1.0 x 22.99) + (1.0 x 1.01) + (1.0 x 12.01) + (3.0 x 16.00) = 84.01 g/mole.To get the percentage of each element using the relation: % composition = [(no. of atoms x its atomic mass) / (molar mass of the compound)] x 100.The % of Na = (1.0 x 22.99) / (84.01) x 100 = 27.365 %.The % of H = (1.0 x 1.01) / (84.01) x 100 = 1.20 %.The % of C = (1.0 x 12.01) / (84.01) x 100 = 14.30 %.The % of O = (3.0 x 16.00) / (84.01) x 100 = 57.13 %.