When a 2.5 mol of sugar (c12h22o11) are added to a certain amount of water the boiling point is raised by 1 celsius degree. if 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? use 3 – 4 sentences to explain your answer. ! will give most

The boiling point of the water by adding 2.5 moles of aluminium nitrate will be changed by 4°Celsius.

When sugar is dissolved in x kg of water:

ΔT₁ = 1°C = 274 K (0°C = 273 K)

Number of moles of sugar dissolved = 2.5 mol

i = Van't Hoff factor of sugar = 1

ΔT₁ = iKf × molality = iKf × moles of sugar/weight of solvent in kg

ΔT₁ = 274 K = 1 × Kf × 2.5 mol / xkg (1)

When aluminium nitrate is dissolved in x kg of water:

Number of moles of aluminium nitrate dissolved = 2.5 mol

Al(NO₃)₃ (aq) = Al₃+ (aq) + 3NO₃⁻ (aq)

i = Van't Hoff factor of aluminium nitrate is 4

Aluminium nitrate being ionic compound will get dissociated into its constituting ions. The value of i of the ionic compound is equivalent to the number of discrete ions in a formula unit of a substance.

ΔT₂ = iKf × moles of Al (NO₃)₃ / weight of solvents in Kg

ΔT₂ = 4 × Kf × 2.5 mol / x Kg (2)

On dividing 1 and 2 we get,

delta T₂ = 4 × 274 K = 4 × 1°C = 4°C

The boiling point of the water by adding 2.5 moles of aluminium nitrate will be changed by 4°C.