What is the molarity of a solution made by dissolving 21.2 g of a sodium hydroxide (naoh) in enough water to make 7.92 l of solution?

Formula for molarity is

Molarity=moles of solvent/solution in liters

In given data

NaOH is 21.2g which is needed to be convert in moles first

As no.of moles=mass in gram/molar mass

Molar mass of NaOH is 39.997g/mol

Putting in formula for mole.we get

No of mole = 21.2g/39.997gper mole

= 0.530mole

Now put these values in molarity equation, we get

Molarity =moles of NaOH/ solution in liter

= 0.530/7.92

=0.067M NaOH

0.067

Explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :