At 325 k, the pressure inside a gas-filled container is 467 kpa. if the pressure inside decreases to 233 kpa, but the volume remains the same, what is the final temperature of the gas?

According to Gay-Lussac’s law, for a fixed mass of gas of constant volume, the pressure is directly proportional to the absolute temperature

Therefore

P1/T1 = P2/T2

Where P1 is initial pressure and T1 is initial temperature

And P2 is final pressure and T2 is final temperature

Substituting these values in the equation

467 kPa / 325 K = 233 kPa / T2

T2 = 162 K

The final temperature of the gas is 162 K

where's the diagram?