What is the temperature of 0.750 mol of a gas stored in a 6,850 ml cylinder at 2.21 atm? use pv=nrt and r=0.0821 (l•atm)/(mol•k) a.)2.95 k b.)5.24 k c.)138 k d.)246 k

Using the formula PV=nRT
we know:
n= 0.750mol
R= 0.0821 (L•atm)/(mol•K)
V= 6850 ml = 6.85 L
P= 2.21 atm
and we need to find T
all you have to do is divide PV by nR and you will find T, like this:

The temperature of the gas is D)246 K

The answer to this problem is. 67