96.3 kj of heat was generated when boiling water. how much water was evaporated?

Here we have to get the amount of water evaporated which generate 96.3 kJ of heat at boiling condition.

The amount of water evaporated is 23.043 g.

We know H = m×s×t, where H = generated heat, m = mass of the material, s = specific heat of the material, t = temperature.

We know the specific heat of water is 4.179 J/g°C.

At boiling condition of water the temperature is 100°C.

The heat generated 96.3 kJ or 9630 J.

On plugging the values we get,

9630 J = m×4.179 J/g°C × 100°C

Thus, 9630 J = m × 417.9 J/g

m =

m = 23.043 g.