Write down the values of m (atomic number or atomic weight) and z (atomic number) for : (1) the element x formed from thorium-232 after six a and four b emissions? (2) the element y formed from uranium-238 after six a and two b emissions. (z=90 for thorium ; z=92 for uranium)

(1) Z = 82, M = 208;  (2)  Z = 82, M = 208

Step-by-step explanation:

(1) Decay of Th-232

The unbalanced nuclear equation is

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

  90 = x + 6×2 + 4(-1), so x =   90 – 12 + 4 =   82

232 = y + 6×4 + 4×0,  so y = 232 – 24      = 208

Z = 82, M = 208

(2) Decay of U-238

The unbalanced nuclear equation is

Then

  92 = x + 6×2 + 2(-1), so x =   92 – 12 + 2 =  82

238 = y + 6×4 +4×0,    so y = 238 – 24     = 214

Z = 82, M = 214

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.