Will mark branliest. calculating percent yield: for the reaction cu + 2agno3 → cu(no3)2 + 2 ag, adding 127 grams of copper to lots of silver nitrate yields 410 grams of silver. what is the percent yield of silver? i'm desperate.

Percent yield = (Actual Yield/ Theoretical Yield) x 100

Given, Actual Yield of silver = 410 grams

Given, mass of copper = 127 g

Atomic mass of copper = 63.546 amu

Formula: Moles = mass / atomic mass

Moles of copper = 127 g/ 63.546 amu = 1.998 mol

Based on the given balanced chemical reaction, the molar ratio between Cu: Ag is 1:2

So 1.998 mol of copper should yield (2 mol Ag/ 1 mol Cu) x 1.998 mol of Cu = 3.996 mol

Calculated mol of Ag = 3.996 mol

Atomic mass of silver = 107.8682 amu

Mass of silver = moles x atomic mass = 3.996 mol x 107.8682 amu = 431 g

Based on the math, the theoretical yield = 431 g

Percent yield of silver = (410g/431g) x 100 = 95. 13%

The answer is 95. 13%

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

the answer is 75.0%.