The molarity (m) of an aqueous solution containing 15.6 g of sucrose, c12h22o11, in 65.5 ml of solution is: 6.96 x 10–4 m. 2.47 x 10–2 m. 0.696 m. 1.33 m.

the molecularity of C12H22O11 is = 12x12+22x1+16x11 = 342 g/mol

molarity (M) = moles / V. solution

moles = mass / 342 = 15,6/342 = 0,0456 moles

=> molarity (M) = 0,0456/0,0655 = 0,696 M

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