Consider the location of barium, chlorine, iodine, and strontium on the periodic table. electronegativities which type of atom has the strongest attraction for electrons in bond formation? barium (ba) chlorine (cl) iodine (i) strontium (sr)

The correct answer is Chlorine (Cl).

Explanation: Electronegativity is the property of an element to attract the shared pair of electron towards itself. In a periodic table, the electronegativity increases as we move from left to right and it decreases as we move from top to bottom.

The location of the given elements are:

Barium (Ba): It belongs to Group 2 and Period 6 of the periodic table.

Chlorine (Cl): It belongs to Group 17 and Period 3 of the periodic table.

Iodine (I): It belongs to Group 17 and Period 5 of the periodic table.

Strontium (Sr): It belongs to Group 2 and Period 5 of the periodic table.

From the above information, Chlorine belongs to the lowest period and greatest group number. Hence, it has the highest electronegativity and will attract the shared pair of electron towards itself strongly.

Therefore, the correct answer is Chlorine (Cl).

The more right you are and the more up you are, the stronger the connection.

Start by going left to right. The two furthest are Iodine and Chlorine (so barium and strontium are eliminated). Then look at that column vertically. Chlorine is further up, so that is your answer.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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chemistry sucks a**

explanation: