Approximately how many grams of sodium chloride (nacl) are required to prepare 500. ml of 3.00 m solution

First convert mL to L:
(500. mL)/(1000L) = .500L

Then convert molarity to moles:
(3.00M)(.500L) = 1.5mol NaCl

Then convert moles of NaCl to grams of NaCl by multiplying it by its molar mass:
(1.5mol NaCl)(58.44g/mol NaCl) = 87.66g NaCl are needed

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