Given: 4al + 3o2 → 2al2o3 in this chemical reaction, how many grams of al2o3 will be produced if 375 grams of al react completely? express your answer to three significant figures. there will be grams of al2o3.

≈ 708

Explanation

Here we have equation as:

                        4 Al     +    3 O₂    →    2 Al₂O₃

As we know:  

                       No of moles = Mass/ Molar mass

Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:

                                            =375 g /27 g/mol

                                               =  13.889 mol

About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.

As we know:  

                            Mass= No of moles/Molar mass  

                      Mass of Al₂O₃ = 6.944 mol × 102  g/mol

                                          = 708.288 g

                               708 of Al2O3   will be produced

Hope it helps!

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.