What mass (in grams) of mgbr2 would be present in 23.7 ml of 0.875 m mgbr2 solution? give your answer to 2 decimal places. (you’ll need your periodic table)

A) 0.875 M of MgBr2 is 0.875 mol/L

B) 23.7 mL = 0.0237 L

0.875 mol => 1 L
x mol => 0.0237 L

Cross multiply
1x = 0.875 × 0.0237
x = 0.0207 mol

>> In 23.7 mL of 0.875 M MgBr2 solution there is 0.0207 moles of MgBr2

C) Molar mass of MgBr2 (*) = 24.305 + (2 × 79.904) = 184.113 g/mol

184.113 g => 1 mol
x g => 0.0207 mol

Cross multiply
1x = 184.113 × 0.0207
x = 3.8111 g

>> 0.0207 moles of MgBr2 is equivalent to 3.81 g of MgBr2
>> In 23.7 mL of 0.875 M MgBr2 solution there is 3.81 g of MgBr2

(*) Use your periodic table

Evaporation: this is when warmth from the sun causes water from oceans, lakes, streams, ice and soils to rise into the air and turn into water vapour (gas). water vapour droplets join together to make clouds! condensation: this is when water vapour in the air cools down and turns back into liquid water.