If you make a solution by dissolving 1.0 mol of fecl3 into 1.0 kg of water, how would the osmotic pressure of this solution compare with the osmotic pressure of a solution that is made from 1.0 mol of glucose in 1.0 kg of water? one-half as large the same twice as large four times as large

Calculating the osmotic pressure of solution:

Osmotic pressure, π = iMRT

FeCl3 gives 1 ion and 3 ions.

i = 1 + 3 = 4

Calculating molarity:

Mass of solvent = 1.0 kg or 1000 g

Mass of =

Total solution mass = 1000 g + 162.20 g = 1162.20 g

Volume of solution =

                                =

Molarity =

Osmotic pressure = 4 * 0.86 M (0.08206 L.atm/(mol.K)(298K)

                              = 84. atm

(We assume T is standard temperature and density of both solutions = 1 g/mL)

Calculating the osmotic pressure of glucose solution:

Osmotic pressure, π = iMRT

i = 1 (as glucose is non electrolyte)

Calculating molarity:

Mass of solvent = 1.0 kg or 1000 g

Mass of glucose =

Total solution mass = 1000 g + 180.16 g = 1180.16. g

Volume of solution =

                                =

Molarity =

Osmotic pressure = 1 * 0.85 M (0.08206 L.atm/(mol.K)(298K)

                              = 21. atm

So when we compare, the osmotic pressures of 1.0 mol of FeCl3 dissolved into 1.0 kg of water is 4 times the osmotic pressure of  1.0 mol of glucose in 1.0 kg of water

hurricanes form in warm water

geosphere and hydrosphere.

this is because the geosphere has to do with geological events, while the hydrosphere controls all water on earth.