What mass of a 15.0% (m/m) naoh solution contains 125 g naoh?

The mass  of 15.0 % (m/m)  NaOH  solution  that contains 125 g NaOH  is  833.33 g

calculation

m/m%  = mass of solute/ mass of solvent x 100

M/M%  = 15.0%   into fraction= 15/100

mass of solute (NaOH) = 125 g

let the mass of solvent  ( NaOH solution) be represented  by Y

Therefore 15/100 = 125/Y

by  cross  multiplication

 =15 x Y =125 x 100

15 y = 12500

divide both side  by 15

y =833.33 g

i think its 5049.

i hope this !