Cobalt has the chemical symbol co and the atomic number 27. how many protons, neutrons, and electrons would be found in an atom of cobalt-58? 31 protons, 31 neutrons, 27 electrons 31 protons, 27 neutrons, 31 electrons 27 protons, 31 neutrons, 27 electrons 27 protons, 27 neutrons, 31 electrons

The answer is 27 Protons, 27 Electrons, and 31 Neutrons. Hope this helps!

27 protons, 31 neutrons, 27 electrons

Explanation:

Atomic number is equal to the number of protons and equal to the number of electrons.  

So 27 = number of protons = Number of electrons.  

Mass number is the sum of the number of proton and neutrons

Mass number = 58  = Number of proton + Number of  neutrons

Number of neutrons = Mass number - Number of protons = 58 - 27 = 31

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol