Question 12 hydrogen gas has a density of 0.090/gl , and at normal pressure and 2.57°c one mole of it takes up 22.4l . how would you calculate the moles in 410.g of hydrogen gas?

The moles in 410 g of hydrogen gas : 201.67

Some of the laws regarding gas can apply to ideal gas (volume expansion does not occur when the gas is heated), :

Boyle's law at constant T,

Charles's law, at constant P,

Avogadro's law, at constant P and T,

So that the three laws can be combined into a single gas equation, the ideal gas equation

In general, the gas equation can be written

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

Hydrogen gas has a density of 0.090, and at normal pressure (1 atm) and 2.57 °C (273+ 2.57 = 275.57K), one mole of it takes up 22.4 l

From here we can input into the ideal gas equation to find an unknown value, molar mass (M)

we have to manipulate this ideal gas equation to find molar mass,

molar mass is the ratio between mass and mole

.... equation 1

Whereas density is the ratio between  mass and volume

.... equation 2

The ideal gas equation becomes

We input the known values

moles in 410 g of hydrogen gas :

The mass of one mole of raindrops  

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moles of NaOH  

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moles of water you can produce  

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Keywords: mole, hydrogen gas, density, normal pressure

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explanation: