What is the net cell reaction for the cobalt-silver voltaic cell? express your answer as a chemical equation?

The net ionic equation for the cobalt-silver voltaic cell is

Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in solution ( which means that are present in the solution) and other half of the cell consists of the Ag electrode immersed in solution ( which means that is present in the solution)

The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a  cathode.

At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.

At Anode :                    

At Cathode:                  

Net ionic equation:  

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.