Consider the following reaction: n2(g) + 3h2(g) 2nh3(g) determine the standard free energy of the the reaction at298k?

Given reaction:

N2(g) + 3H2(g) → 2NH3(g)

The standard free energy change is given as:

ΔG° = ∑ nΔGf(products) - ∑ nΔGf(reactants)

      = [2ΔGf(NH3(g))] - [ΔGf(N2(g)) + 3ΔGf(H2(g))]

       = [2(-16.48)] - [ 1(0) + 3(0)] = -32.96 kJ

Ans: Free energy of the reaction is -32.96 kJ, i.e. reaction is spontaneous.

i think is conclusions.i think so

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )