The burning of 48.7 g of zns in the presence of oxygen gives 220.0 kj of heat. what is h for the reaction as written below?

The ΔH of the reaction when 48.7 grams of ZnS reacts with oxygen is -55.23 kJ.

Explanation:

Amount of ZnS = 48.7 grams

Molecular mass of ZnS = 97.474 g/mol

Moles of ZnS.:

According to reaction, 2 moles of ZnS gives energy = -220 kJ

So, 0.5021 moles of ZnS gives energy :

The ΔH of the reaction when 48.7 grams of ZnS reacts with oxygen is -55.23 kJ.

the answer is d. 74.02