Lino3(aq) and na2co3(aq).if a solid forms when solutions containing these salts are mixed, write the ionic equation.

The net ionic equation :

Explanation:

When aqueous solution of lithium nitrate and sodium carbonate are a=mixed together they give solid precipitate of lithium carbonate and aqueous solution of sodium nitrate.

When lithium nitrate in its aqueous solution gives lithium ions and carbonate ions.

When sodium carbonate in its aqueous solution gives lithium ions and carbonate ions.

When sodium nitrate in its aqueous solution gives lithium ions and carbonate ions.

Cancelling out common ions i.e. spectators ions from both the sides, we get the net ionic equation :

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

i'm assuming that the correct answer is indeed the first one/ "a"..