The reaction between 2-methyl-2-pentanol and hbr to yield 2-bromo-2-methylpentane is probably: an sn2-type reaction involving the protonated alcohol as the substrate. an epoxidation reaction. an sn1-type reaction involving the protonated alcohol as the substrate. an e2-type reaction involving the protonated alcohol as the substrate. an e1-type reaction involving the protonated alcohol as the substrate.

The correct answer is an type reaction involving the protonated alcohol as the substrate.

Explanation: reactions are a type of nucleophilic reactions. These reactions are considered as the unimolecular reactions in which only 1 component is used to determine the rate of the reaction.

This reactions involved the generation of a carbocation as an intermediate.

For the reaction of 2-methyl-2-pentanol and HBr, the intermediate formed is  protonated alcohol which yields the product 2-bromo-2-methylpentane.

Reaction is attached in the image below.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.