Write the formula for a complex formed between cr3 and 2,2\'-bipyridine (c10h8n2), with a coordination number of 6.

The reaction is:

Cr₃⁺ +3 C₁₀H₈N₂ → [Cr(C₁₀H₈N₂)₃]³⁺

2,2\'-bipyridine is bidentate ligand and neutral. It exhibits two N terminal, thus, it functions as bidentate ligand.

Therefore, three 2,2\'-bipyridine ligand fulfills the six coordination number of Cr₃⁺.

The formula for the complex is [Cr(C₁₀H₈N₂)₃]³⁺

your answer would be “dry”