Chemistry! ! ! 1. organic functional a. give characteristic properties to compounds that contain them. b. always contain oxygen. c. always contain a double or triple bond. d. are present in every organic compound. 2. which of the following statements about denaturing is true? a. denaturing occurs when a protein unfolds. b. denaturing occurs when a carbohydrate is heated. c. denaturing does not affect the tertiary structure of an enzyme. d. denaturing increases the rate of a chemical reaction. 3. which of the following solutions would have a ph value greater than 7? a. [oh-] = 2.4 × 10^-2 m b. [h3o+] =1.53 × 10^-2 m c. 0.0001 m hcl d. [oh^-] = 4.4 × 10^-9 m

1. Functional groups

a. Give characteristic properties to compounds that contain them.

Explanation:

a. is correct. This is what functional groups do: they change the chemical and physical properties of a compound.

b. is wrong. For example, CN and SH are functional groups that contain no oxygen.

c. is wrong. For example, OH and SH contain no double or triple bonds.

d. is wrong. There are no functional groups in alkanes.

2. Denaturing

a. Denaturing occurs when a protein unfolds.

Explanation:

Denaturing involves the breaking of the attractive forces that hold the protein in its characteristic shape.

With these bonds broken, the protein structure unfolds.

b. is wrong. Denaturing is the term applied only to proteins

c.  is wrong. Denaturing destroys the 3D structure of an enzyme.

d. is wrong. Denaturing an enzyme destroys the catalytic action of an enzyme. Denaturing decreases the rate of an enzyme-catalysed reaction.

3. Identifying basic solutions

a. [OH⁻] = 2.4 × 10⁻² mol·L⁻¹

Explanation:

To be basic, a solution must have [OH⁻] > 1 × 10⁻⁷ mol·L⁻¹ or

[H₃O⁺] < 1 × 10⁻⁷ mol·L⁻¹.

a. is correct, because [OH⁻] > 1 × 10⁻⁷ mol·L⁻¹

b. is wrong, because [H₃O⁺] > 1 × 10⁻⁷ mol·L⁻¹.

c. is wrong, because [H₃O⁺] > 1 × 10⁻⁷ mol·L⁻¹. The solution is acidic.

d. is wrong. [OH⁻] < 1 × 10⁻⁷ mol·L⁻¹. The solution is acidic.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.