Calculate the ph at the equivalence point for the titration of 0.230 m methylamine (ch3nh2) with 0.230 m hcl. the kb of methylamine is 5.0× 10–4.

The pH at the equivalence point for the titration will be 0.65.

Solution:

Let the concentration of be x

Initial concentration of , c = 0.230 M

at eq'm  c-x                         x                    x

Expression of :

Since ,methyl-amine is a weak base,c>>x so .

Solving for x, we get:

Given, HCl with 0.230 M , it dissociates fully in water which means = 0.230 M

will result in neutral solution, since

Remaining after neutralizing ions

The pH at the equivalence point for the titration will be 0.65.

the answer is 0.42 is that is an option. this question provides no info