What volume of h2o is formed at stp when 6.0g of al is treated with excess naoh? naoh + al + h2o —-> naal(oh)4 + h2 (g)

Answer : The volume of is 14.784 L.

Solution : Given,

Mass of Aluminium = 6 g

Molar mass of Aluminium = 27 g/mole

First we have to calculate the moles of aluminium.

Moles of Al =

The given balanced reaction is,

From the reaction, we conclude that

2 moles of Al react with the 6 moles of

0.22 moles of Al react with of

At STP,  1 mole contains 22.4 L volume

As, 1 mole of contains 22.4 L volume of

0.66 moles of contains volume of

Therefore, the volume of is 14.784 L.                                                                                        

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey

c8h10 is your answerr