Find the cell potential for a system whose ∆g = +55 kj and 3 moles of electrons are exchanged.

- cell potential = -0.19 volts

Solution:- The equation that shows the connection between and cell potential, E is written  as:

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is .

It asks to calculate the value of E, so let's rearrange the equation:

Let's plug in the values in it:

since,

Where C stands for coulombs and V stands for volts.

So,

E = -0.19 V

So, the cell potential is -0.19 volts.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.