Suppose a bag full of ice 450g at 0.0degrees celsius set on the counter and begin to melt to liquid water how much how much energy much be absorbed by the ice 2/3 of it melt

Ice melts at a constant temperature of 0° C

heat absorbed by ice while melting = mass of ice melted × Ice's heat of fusion               eq1

Mass of ice = 450g

need to calculate 2/3 of its melted :-  2/3 of 450 =  300g

mass of ice melted = 300g and ice's heat of fusion( 333.55J/gm)

                                           (value of ice's heat of fusion is universal constant)

from eq1 :-  Heat absorbed = 300 ×  333.55  =  100065 J =>   100.065Kj