What volume of 0.175 m na3po4 solution is necessary to completely react with 95.4 ml of 0.102 m cucl2?

 The  volume  of 0.175 M   Na3PO4   solution    that is necessary  to completely  react  withn   95.4 ml  of  0.102 M  cuCl2  is

calculation

  Step 1: write  the equation for reaction

3CuCl2 (aq)  + 2Na3Po4 →  Cu3(PO4)2  + 6 NaCl

Step 2 : find the  moles  of CuCl2

moles  =  molarity  x  volume in liters

 volume in liters  =  95.4  /1000 =0.0954 L

moles  is therefore = 0.0954 L  x  0.102 M= 0.00973 moles

Step : use the mole  ratio to calculate  the  moles of Na3Po4

The mole ratio  of  CuCl2 : Na3PO4  is 3:2  therefore  = 0.00973 x2/3= 0.00649  moles

Step  4 :   find  the volume of  Na3PO4

volume  = moles/molarity

= 0.00649 mole /  0.175=0.037 M

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the temperature of the gas, in k, not celsius.