The net reaction of the calvin cycle is the conversion of co2 into the three-carbon sugar g3p. along the way, reactions rearrange carbon atoms among intermediate compounds and use the atp and nadph produced by the light reactions. in this exercise, you will track carbon atoms through the calvin cycle as required for the net production of one molecule of g3p. for each intermediate compound in the calvin cycle, identify the number of molecules of that intermediate and the total number of carbon atoms contained in those molecules. as an example, the output g3p is labeled for you: 1 molecule with a total of 3 carbon atoms. labels may be used once, more than once, or not at all. hints

Many reactions take place in aqueous solution. when potential reactants are mixed, a reaction will occur if there is some driving force that favors the formation of products. it is often convenient to categorize reactions in terms of these driving forces: precipitate formation, in which an insoluble solid is formed, weak electrolyte formation, as in a neutralization reaction involving water, or transfer of electrons, as in a redox reaction. these reactions can be represented by full molecular equations, which contain all species in the reaction mixture, or by net ionic equations, which show only the species that actually undergo a change. the latter does not contain the spectator ions, which do not undergo a net change or do not take part in the reaction. part a when the following two solutions are mixed: k2co3(aq)+fe(no3)3(aq) the mixture contains the ions listed below. sort these species into spectator ions and ions that react. drag the appropriate items to their respective bins. view available hint(s) spectator ions ions that react part b what is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? assume that the contribution of protons from h2so4 is near 100 %.ba(oh)2(aq)+h2so4(aq)→ express your answer as a chemical equation. view available hint(s) nothing provide feedback

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