If 22 ml of 0.137m mgcl2 is needed to completely react 15 ml of agno3 solution, what is the molarity of agno3?

The molarity   of AgNO3  is 0.401  M

  calculation

Step 1:  write the chemical equation  for  reaction

MgCl2 + 2AgNO3 →  Mg(No3)2   +  2 AgCl

Step 2: calculate the moles of  MgCl2

moles  =  molarity  x volume  in liters

volume in liters=22/1000=  0.022 L

molarity = 0.137 M   or  0.137 mol/L

moles  is therefore= 0.137 mol/l  x  0.022 L  =3.01 x10^-3  moles

Step 3: use the mole ratio  to determine the moles  of AgNO3

 The mole  ratio  of MgCl2: AgNO3  is 1:2   therefore  the moles of AgNo3  is

= 3.01 x 10^-3 moles x  2/1= 6.02 x 10^-3  moles

Step 4:  find the molarity   of AgNO3

molarity = moles /volume in liters

volume in liters = 15/1000=0.015 L

molarity is therefore =( 6.02 x 10^-3)  /0.015 =  0.401 M

1.solid

2.carbon dioxide

3.helium

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