What is the heat required to vaporize 650 grams of a liquid with a heat of vaporization of 723 joules/gram? a. 0.90 j b. 1.1 j c. 73 j d. 1,370 j e. 470,000 j

 The heat required to   vaporize 650 grams  of liquid    with a heat  of vaporization  of 723  joules/grams  is 470,000  J ( answer  E)

calculation

Heat (Q)  =  m Hv   where,

 m(mass)=  650  g

 HV(   heat of vaporization)  = 723 J/g

heat  is therefore =  650 g  x 723  J/g  =469950 J

round off  469950 j into nearest 10,000 =  470,000 J ( answer E)

Hello!

What is the heat required to vaporize 650 grams of a liquid with a heat of vaporization of 723 joules/gram?

We have the following data:  

We apply the data to the formula, see:

E. 470,000 J

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I Hope this helps, greetings ... Dexteright02! =)

2b2t

explanation:

2b2t