What is the volume (in liters) of 1.00 mole of krypton gas that has a pressure of 1140 mm hg and a temperature of 25.0°c? (r= 0.0821 l atm/ mol k)?

The  volume (in  liters )  of 1.00   moles  of  krypton gas   is 16.31 L

 Calculation

The volume of krypton  is calculated using ideal gas  equation

that is PV=nRT  where

P(pressure) =1140 mm hg

convert  1140 mmhg  into atm

= 1 atm =  760  mmhg

  ? atm  = 1140 mm hg

by cross  multiplication

= (1 atm x1140  mmhg) /760  mmhg = 1.5 atm

V (volume) =   ?  L

n( number of moles) = 1.00 mole

R (gas constant) = 0.0821  L atm / mol.K

T (temperature) = 25 c into kelvin = 25+273 = 298 K

make  v  the subject of the formula  by dividing both side by P

V   = nRT/P

V= [(1.00 mole  x 0.0821  L.atm/mol.k  x 298 K) / 1.5 atm ] =16.31 L

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."