A430. ml solution of 0.230 m hbr(aq) is mixed with a solution of 225 ml of 0.350 m hclo4(aq). how many moles of h+(aq) are present in the final solution?

Given:

volume of HBr = 430 ml = 0.430 L

Molarity of HBr = 0.230 M

Volume of HClO4 = 225 ml = 0.225 L

Molarity of HClO4 = 0.350 M

To determine:

Total moles of H+ when HBr and HClO4 are mixed

Explanation:

HBr and HClO4 are strong acids. Hence:

Concentration of H+ from HBr = 0.230 M

Concentration of H+ from HClO4 = 0.350 M

Now:

# moles of H+ from HBr = 0.430 L * 0.230 moles/L = 0.0989 moles

# moles of H+ from HClO4 = 0.225 L * 0.350 moles/L = 0.0788 moles

Total moles of H+ = 0.0989 + 0.0788 = 0.1777 moles

Ans: Total # moles of H+ is 0.178

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

if you mean hydrogen and oxygen then water is the product