Use the balanced equation to work the following problem: cacl2 + 2agno3 → 2 agcl + ca(no3)2 how many grams of agcl (molar mass=143 g/mol) is formed when 1.00 gram of agno3 (molar mass=170 g/mol) reacts? 1.00 g 0.00588 g 1.19 g 0.841 g

The mass of AgCl formed in the reaction is 0.841 grams.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of silver nitrate = 1.00 g

Molar mass of silver nitrate = 170 g/mol

Putting values in equation 1, we get:

For the given chemical equation:

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of AgCl

So, of silver nitrate will produce = of AgCl

Now, calculating the mass of AgCl by using equation 1.

Moles of AgCl =

Molar mass of AgCl = 143.32 g/mol

Putting values in equation 1, we get:

Hence, the mass of AgCl formed in the reaction is 0.841 grams.

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