In this reaction, how does the rate of forward reaction vary with the concentration of the product? 2h2s(g) ⇌ 2h2(g) + s2(g) it increases with an increase in the concentration of s2(g). it decreases with a decrease in the concentration of h2(g). it increases with a decrease in the concentration of h2(g). it decreases with an increase in the concentration of s2(g). it decreases with increase in the concentration of h2(g). multiple answers

C) It increases with a decrease in the concentration of . D) It decreases with increase in the concentration of .

Explanation: According to Le Chatelier's principle, if an equilibrium reaction is disturbed, the reaction would try to undo the change imposed.

Thus if the concentration of the products in increased, the reaction would shift in a direction where the concentration of products is decreasing i.e in backward direction.

If the concentration of the products in decreased, the reaction would shift in a direction where the concentration of products is increasing i.e in forward direction.

When the concentration of either of the products, i.e or is increased, the reaction will shift in backward direction and the rate of forward direction decreases.

the product of the pressure and volume is also constant

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.