How many moles of gas does it take to occupy 120 l at a pressure of 233 kpa and a temperature of 340 k? a. 6.4 moles b. 7.7 moles c. 8.6 moles d. 9.9 moles

The correct answer is option D.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 233 kPa

1 atm = 101.325 kPa

V = Volume of gas = 120 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 340 K

Putting values in above equation, we get:

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).