Which combination of temperature and pressure correctly describes standard temperature and pressure, stp? a) 0 degrees c and 101 kpa b) 1 degrees c and 0 kpa c) o degrees c and 22.4 kpa d) 100 degrees c and 100 kpa

A

0 degrees and 101 kPa are the conditions that describe the standard temperature and pressure. When expressed in K, the standard temperature 0 degrees equals 273.5 K. Also the standard pressure 101 kPa equals 760 mmHg or 1 Atm.

Combination of temperature and pressure correctly describes STP: A) 0 degrees C and 101 kPa

Standard conditions for temperature and pressure are used as a reference in certain calculations or conditions

There are several standards used by various organizations such as IUPAC or NIST

There are 2 conditions that are usually used as a reference in chemical calculations (mainly for determining the volume per mole of a gas or the molar volume), namely:

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

Conditions at T 25 ° C and P 1 atm are stated by RTP (Room Temperature and Pressure). Vm in this condition = 24.4 liters / mol

So 1 atm if converted to Pascal:

1 atm = 101,325 kPa

Which equation agrees with the ideal gas law

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Which law relates to the ideal gas law

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