Predict the products of the following reaction based upon solubility rules. (separate substances in a list with a comma. include states-of-matter under the given conditions in your answer. cl-1 is soluble unless with pb+2, h2+2, and ag+1. co3 is unsoluble unless with li+, na+, k+, rb+, cs+, nh4+. rb2co3(aq) + cacl2(aq) → ?

Hey there!:

As per solubility rules inorganic compounds that are soluble are

:Ammonium (NH4⁺),potassium (K⁺), sodium (Na⁺) : All ammonium, potassium and sodium salts are soluble. Exceptions:some transition metal compounds.

Bromides (Br⁻), chlorides (Cl⁻) and iodides (I⁻): Most bromides are soluble. Exceptions: salts containing silver, lead, and mercury.

So Rb2Cl2 is expected to be soluble.

 As per solubility rules inorganic compounds that are insoluble are  : Carbonates (CO₃²⁻), chromates (CrO₄²⁻), phosphates (PO₄³⁻), silicates (SiO₄²⁻): All carbonates, chromates, phosphates and silicates are insoluble. Exceptions: those of ammonium, potassium and sodium.

So CaCO3 is insoluble and precipitates

Therefore:

The completed equation is  :

Rb2CO3(aq)  + CaCl2(aq) → CaCO3(s) + Rb2Cl2(aq)

Hope that helps!

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