How many grams of naf form when 0.589 mol of hf react with excess na2sio3?

6.18 g

Explanation:

We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

:                                             41.99  

                 Na₂SiO₃ + 8HF ⟶ 2NaF + H₂SiF₆ + 3H₂O  

n/mol:                         0.58    

1. Use the molar ratio of NaF:HF to calculate the moles of NaF.

2. Use the molar mass of NaF to calculate the mass of NaF.

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