If 34.7 g of agno₃ react with 28.6 g of h₂so₄ according to this unbalanced equation below, how many grams of ag₂so₄ could be formed? agno₃(aq) + h₂so₄ (aq) → ag₂so₄ (s) + hno₃ (aq)

The  number  of grams   of Ag2SO4  that could be formed  is   31.8  grams

    calculation

Balanced   equation is  as below

2 AgNO3 (aq)  + H2SO4(aq)  →  Ag2SO4 (s)   +2 HNO3 (aq)

that is  moles of  AgNO3= 34.7 g / 169.87  g/mol= 0.204 moles

             moles of  H2SO4 =  28.6  g/98  g/mol  =0.292  moles

   that is;

that  is  0.102   moles  x  311.8  g/mol= 31.8 grams

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year