How many milligrams of iodine would be a typical amount in a 60.-kg adult?

                 9.03 mg

                         For this question I was supposed to make a search using the keyword "Chemical composition of the human body" and found the amount of Iodine as,

   Element                               Atoms / 70 Kg Man

      Iodine                                           5 × 10¹⁹

We can calculate amount of Iodine / 60 Kg as,

                   70 Kg Man contained  =  5 × 10¹⁹ I atoms

So,

                       60 Kg Man will contain  = X  I atoms

Solving for X,

                      X  =  (60 Kg × 5 × 10¹⁹ I atoms) ÷ 70 Kg

                       X =  4.28 × 10¹⁹ I Atoms

Now, convert number of I atoms to Mass as,

Step 1: Calculate Moles of I,

                   Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Putting value,

                   Moles  =   4.28 × 10¹⁹ ÷ 6.022 × 10²³ Atoms.mol⁻¹

                   Moles  =  0.00007116762 mol

Step 2: Calculate Mass of Mass:

                   Moles  =  Mass ÷ M.Mass

Solving for Mass,

                   Mass  =  Moles × M.Mass

Putting values,

                   Mass  =  0.00007116762 mol × 126.90 g.mol⁻¹

                   Mass  =  0.00903117141 g

Or,

                   Mass =  9.03 mg

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hope i !